(x-2)^2-3x=x(x+1)-4

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Solution for (x-2)^2-3x=x(x+1)-4 equation: 



(x-2)^2-3x=x(x+1)-4

We move all terms to the left:

(x-2)^2-3x-(x(x+1)-4)=0

We add all the numbers together, and all the variables

-3x+(x-2)^2-(x(x+1)-4)=0



We calculate terms in parentheses: -(x(x+1)-4), so:

x(x+1)-4

We multiply parentheses

x^2+x-4

Back to the equation:

-(x^2+x-4)



We get rid of parentheses

-x^2-3x+(x-2)^2-x+4=0

We add all the numbers together, and all the variables

-1x^2-4x+(x-2)^2+4=0

We move all terms containing x to the left, all other terms to the right

-1x^2-4x+(x-2)^2=-4

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